Comments for My "I Need Help With A Math" Place http://math.cynical-dreamer.net Where people come to help me with math ;-) Thu, 15 Jul 2010 15:53:33 +0000 hourly 1 http://wordpress.org/?v=3.0 Comment on Graphing a System of Linear Inequalities by zakłady bukmacherskie http://math.cynical-dreamer.net/?p=3&cpage=1#comment-182 zakłady bukmacherskie Thu, 15 Jul 2010 15:53:33 +0000 http://math.cynical-dreamer.net/?p=3#comment-182 I want to start blogging too, what do you think, which blog cms is good for noob? I want to start blogging too, what do you think, which blog cms is good for noob?

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]]> Comment on Graphing a System of Linear Inequalities by R6 lady http://math.cynical-dreamer.net/?p=3&cpage=1#comment-179 R6 lady Thu, 01 Jul 2010 17:34:00 +0000 http://math.cynical-dreamer.net/?p=3#comment-179 Electricity is really just organized lightning. Sent from my iPhone 4G Electricity is really just organized lightning.

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]]> Comment on Graphing a System of Linear Inequalities by Mr. Teach http://math.cynical-dreamer.net/?p=3&cpage=1#comment-2 Mr. Teach Thu, 25 Feb 2010 21:58:28 +0000 http://math.cynical-dreamer.net/?p=3#comment-2 It sounds like you need help with graphing the lines. I don't know what book you are using, but find a section on graphing lines. The way I tell my students to do this is solve the inequality for 'y'. (The same way you would if there was an equal sign, just remember to flip the symbol if you divide/multiple by a negative on both sides.) So your two inequalities will look like this: y ≤ 2x - 3 y ≥ (-1/2)x + 4 Now graph these two lines as if the had an equal sign (y=mx+b). "m" is the slope, and "b" is the y=intercept. Take the first inequality. Put a point at the y-interept of -3. Your slope is 2/1 (rise/run), so from the intercept count up two units and right one unit; put a second point and repeat from that point. Connect the points to draw your line. Do the same with the second inequality. This time your y-intercept is at positve 4, and your slope is (-1/2). This means from the intercept count down one and to the right two. Repeat and draw your line. Now find your test point,(0,0), and shade accordingly. Hope this helps. It sounds like you need help with graphing the lines. I don’t know what book you are using, but find a section on graphing lines. The way I tell my students to do this is solve the inequality for ‘y’. (The same way you would if there was an equal sign, just remember to flip the symbol if you divide/multiple by a negative on both sides.) So your two inequalities will look like this:

y ≤ 2x – 3
y ≥ (-1/2)x + 4

Now graph these two lines as if the had an equal sign (y=mx+b). “m” is the slope, and “b” is the y=intercept. Take the first inequality. Put a point at the y-interept of -3. Your slope is 2/1 (rise/run), so from the intercept count up two units and right one unit; put a second point and repeat from that point. Connect the points to draw your line. Do the same with the second inequality. This time your y-intercept is at positve 4, and your slope is (-1/2). This means from the intercept count down one and to the right two. Repeat and draw your line.

Now find your test point,(0,0), and shade accordingly. Hope this helps.

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